# Past Questions And Answers For NNPC – 2023

By | November 16, 2023

# Past Questions And Answers For NNPC – 2023

This content provides past questions and answers for the Nigerian National Petroleum Corporation (NNPC) 2023 exam.

These Past Questions And Answers  For NNPC are compiled to help you pass the test easily. In the past, the questions were administered by Philips consulting or WAEC (West African Examination Council)

The test is in four sections and a total of 120 questions for 120 minutes The test sections include:

1. Quantitative reasoning questions
2. Verbal Reasoning
3. Spatial / Abstract reasoning
4. General knowledge/ Current affairs.

(Occasionally, some field-specific questions may appear under the general knowledge section of the test depending on what position the candidate applies for.)

## FREE SAMPLE OF NNPC PAST QUESTIONS AND ANSWERS

Beyond just reading, please make sure you set a timer for yourself and practice each section according to the allotted time. Your Speed and Accuracy are key. Also, be current with the news and happenings in Nigeria. Good luck!

1. There is a pole in a lake. One-half of the pole is in the ground, another one-third of it is covered by water, and 12 ft is out of the water. What is the total length of the pole in ft?

A 12 ft

B 34 ft

C 56 ft

D 64 ft

E 72 ft

The correct answer is option [E]

Solution:

Fraction of pole in the ground = 1/2 Fraction of pole

covered by water = 1/3

Fraction of pole in the ground and covered by water =

1/2+ 1/3 = (3 + 2)/6 = 5/6

Fraction of pole out of water = 1 – 5/6 = 1/6 Thus, one sixth

of the pole (out of water) is 12 ft. So, total length

of pole = 72 ft.

It may be noted that:

Length of pole in the ground = 72/2 = 36 ft. Length of

pole covered by water = 72/3 = 24 ft. Length of pole

out of water = 12 ft.

Total = 36ft + 24ft + 12ft = 72ft

1. Boneri was 24 when his son Ibifuro was born. If Boneri is now 3 times as old as Ibifuro, how many years ago was Boneri 4 times as old as Ibifuro?

A 4

B 6

C 8

D 12

E 18

The correct answer is option [A]

1. Amakiri bought a bike for N20 and gave the bike dealer a cheque for N30 to pay for it. The bike dealer persuaded a shopkeeper to change the cheque for him. Amakiri having received his N10 change, rode off on the bike and was not seen again. Later, the cheque was found to be valueless and the bike dealer had to refund the shopkeeper the amount he had received. The bike dealer had bought the bike for N10. How much did the bike dealer lose altogether?

A N40

B N30

C N20

D N10

E The bike dealer did not lose any money

The correct answer is option [C], Reason being that he lost N20. N10 as change for the cheque and N10 for the bike originally.

1. The drive from Oakland to Pinewood was a tricky one. I covered the uphill distance of 55 miles at 35 miles per hour. The return journey from Pinewood to Oakland was downhill, and I managed to drive at 63 miles per hour. What was my average speed for the entire journey?

A 60

B 55

C 50

D 45

E 40

The correct answer is option [D]

Solution:

It is important to note that

Average speed = Total distance / Total time. Total distance = 2

x 55 miles.

Time for uphill journey (from Oakland to Pinewood) = 55 / 35

hours.

Time for downhill journey (from Pinewood to Oakland) = 55

/ 63 hours.

Total time = (55 / 35) + (55 / 63) = 22 / 9 hours.

Average speed = Total distance / Total time = 45 miles per hour

1. If I give you seven apples, you will then have five times as many as I would then have, however, if you give me seven apples, we will then both have the same number of apples. How many apples do we currently have?
A I have 24 apples and you have 18 apples.

B I have 10 apples and you have 32 apples.

C I have 18 apples and you have 24 apples.

D I have 14 apples and you have 28 apples.

E I have 12 apples and you have 20 apples.

The correct answer is option [D]

1. If it takes Seyi twenty minutes to boil an egg in 1.5 litres of water, how long will it take Ala who is 3 years older than Seyi to boil 4 eggs in 1.5 litres of water?

A 10 minutes

B 20 minutes

C 25 minutes

D 5 minutes

E 80 minutes

The correct answer is option [B]

1. Amakiri spent N125 for a camera and some film. The camera cost N100 more than the film. What percent of the cost of the two items did Amakiri spend for the camera?

A 40%

B 90%

C 60%

D 100%

E 20%

The correct answer is option [B]

1. How many two cent stamps are there in a dozen?

A 2

B 10

C 12

D 24

E 30

The correct answer is option [C], Reason being that a dozen of anything is twelve (12)

1. The price of garri rose by 40% last week and fell by 40% this week. What is the total rise or fall in Percentage?

A 40%

B 16%

C 20%

D 100%

E 67%

The correct answer is option [B]

1. The average weight of a class of 24 students is 36 years. When the weight of the teacher is also included, the average weight Increases by 1kg. What is the weight of the teacher?

A 37kgs

B 45kgs

C 61kgs

D 72kgs

E 75kgs

The correct answer is option [C]

1. Mr. Kalada is three times as old as his son. After fifteen years, Mr. Kalada will be twice as old as his son’s age at that time. Hence, Mr. Kalada’s present age is——–

A 48

B 45

C 42

D 36

E 28

The correct answer is option [B]

1. What number comes next in this sequence? 917452, 97452,

9745, 975,?

A 975

B 974

C 97

D 95

E 94

The correct answer is option [C], Reason being that the least digit in each number gets dropped.

1. The average cost of 5 oranges and 4 guava is 36 naira. The

average cost of 7 oranges and 8 guava is 48 naira.

What is the total cost of 24 oranges and 24 guava?

A 1044 naira

B 2088 naira

C 720 naira

D 324 naira

E 198 naira

The correct answer is option [B]

14) What is the value of PS in the triangle below?
A.
B. 10
C. 11
D. 13
E   15
Use the Pythagorean Theorem twice, unless you recognize the common right triangle in the figure.
Since PR = 20 and QR = 16, PQR is a 3x-4x-5x right triangle with x = 4. Then PQ = 12, and PQS is a
right angle triangle whose legs are 5 and 12. The hypotenuse, PS, therefore is 13.

15)
Page 9

A. 40
B. 45
C. 50
D. 55
E. 57
Solution
Since lines l and k are parallel, the angle marked y in the given diagram and the sum of the angles
marked x and 45 are equal:
Y = x + 45 y – x = 45.the answer is (45).

16) In an office, there was a small cash box. One day Ann took half of the money plus \$1 more. Then
Dan took half of the money plus \$1 more. Stan then took the remaining \$11. How many dollars were
originally in the box?
A. \$50
B. \$45
C. \$42
D. \$40
E. \$38
Solution
You can avoid some messy algebra by working backward. Put back the \$11 Stan took; then put back the
extra \$1 that Dan took. There is now \$12, which means that, when Dan took his half, he took \$12. Put that
back. Now there is \$24 in the box. Put back the extra \$1 that Ann took. The box now has \$25, so before
Ann took her half, there was \$50. The answer is (\$50).

17) Each of the 10 players on the basketball team shot 100 free throws, and the average number of
baskets made was 75. When the highest and lowest scores were eliminated the average number of
baskets for the remaining 8 players was 79. What is the smallest number of baskets anyone could have
A. 22
B. 20

C. 18
D. 16
E. 14
Since the average of all 10 players was 75, the total number of baskets made was 10 × 75 = 750. Also,
since 8 of the player had an average of 79, they made a total of 8 × 79 = 632 points. The other 2
players, therefore, made 750- 632 = 118 baskets. The most baskets that the player with the highest
number could have made was 100, so the player with the lowest number had to have made at least 18.

18) Karen played a game several times. She received \$5 every time she won and had to pay \$2
every time she lost. If the ratio of the number of times she won to the number of times she lost was
3:2, and if she won a total of \$66, how many times did she play the game?
A. 30
B. 35
C. 40
D. 45
E. 48
Karen won 3x times and lost 2x times, and thus played a total of 5x games. Since she got \$5 every time
she won, she received \$5(3x) = \$15x. Also, since she paid \$2 for each loss, she paid out \$2(2x) = \$4x.
Therefore, her net winning were \$15x – 4x = \$11x, which you are told was \$66. Then, 11x = 66 ⇒ x = 6,
and so 5x = 30.

19) Since 1950, when Martin graduated from high school, he has gained 2 pounds every year. In
1980 he was 40% heavier than in 1950. What percent of his 1995 weight was his 1980 weight?
A. 80
B. 85
C. 87.5
D. 90
E. 95

Solution
Let x = Martin’s weight in 1950. By 1980, he had gained60 pounds (2 pounds per
year for 30 years) and was 40% heavier:
60 = 0.40x x = 60 ÷ 0.4 = 150. In 1980, he weighed 210 pounds, 15 years later, in 1995, he weighed
240:
210/240= 7/8= 87.5%. The answer is C.

20) Henry drove 100 miles to visit a friend. If he had driven 8 miles per hour faster than he did, he
would have arrived in of the time he actually tokes. How many minutes did the trip take?
A. 100
B. 120
C. 125
D. 144
E. 150

21) Two printing presses working together can complete a job in 2.5 hours. Working alone, press
A can do the job in 10 hours. How many hours will press B take to do the job by itself?
A. 10/3
B. 4
C. 5
C. 25/4
E. 15/12
Multiply each term by 10x: 2.5x + 25 = 10x
.Subtract 2.4x from each other: 25 = 7.5x
. Divide each side by 7.5: x = 3 hours. The answer is A.

22) Approximately what percentage of Ace Marketing’s total business is accounted for by their three
smallest clients?
A. 18%
B. 17%
C. 20%
D. 16%
E. 22%
Explanation: The total value of Ace’s business is \$41,427 (marketing) plus \$40,614 (personnel) which gives
\$82,041. Since we know that Aardvark account for 54% of the business, the quickest way to work out
how much the three smallest clients account for is to calculate how much Blue Arrow accounts for
(\$21,659 which is 26%), add this to the
54% to give 80%, which leaves 20% to be accounted for by the smallest three

23) Approximately what percentage of Ace Marketing’s total business is for Aardvark Cellular?
A.49%
B. 57%
C. 50%
D. 54%
E. 56%
Explanation: The total value of Ace’s business is \$41,427 (marketing) plus \$40,614 (personnel) which gives
\$82,041. Aardvark Cellular account for (21,340+22,749 =) \$44,089.
This equates to (44,089/82,041) * 100 = 54%.

24) If flyers for Aardvark Cellular cost \$150 per thousand. Approximately, how many thousand have
been produced?
A. 23
B. 20
C. 17
D. 14
E. 18

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